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12^2+35^2=x^2
We move all terms to the left:
12^2+35^2-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+1369=0
a = -1; b = 0; c = +1369;
Δ = b2-4ac
Δ = 02-4·(-1)·1369
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-74}{2*-1}=\frac{-74}{-2} =+37 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+74}{2*-1}=\frac{74}{-2} =-37 $
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